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mysqli_connect

(PHP 5, PHP 7)

mysqli_connectAlias of mysqli::__construct()

Description

This function is an alias of: mysqli::__construct()

Although the mysqli::__construct() documentation also includes procedural examples that use the mysqli_connect() function, here is a short example:

Examples

Example #1 mysqli_connect() example

<?php
$link 
mysqli_connect("127.0.0.1""my_user""my_password""my_db");

if (!
$link) {
    echo 
"Error: Unable to connect to MySQL." PHP_EOL;
    echo 
"Debugging errno: " mysqli_connect_errno() . PHP_EOL;
    echo 
"Debugging error: " mysqli_connect_error() . PHP_EOL;
    exit;
}

echo 
"Success: A proper connection to MySQL was made! The my_db database is great." PHP_EOL;
echo 
"Host information: " mysqli_get_host_info($link) . PHP_EOL;

mysqli_close($link);
?>

The above examples will output:

Success: A proper connection to MySQL was made! The my_db database is great.
Host information: localhost via TCP/IP
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User Contributed Notes 3 notes

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0
thamizh82 at gmail dot com
1 month ago
$con=mysqli_connect("localhost","my_user","my_password","my_db");

var_dump($con);  -> Return mysql object.

$conn = mysqli_connect(NULL, $user, $pass);
$conn = mysqli_connect('NULL', $user, $pass);
Return Same object given before. Not thrown false or error.

$conn = mysqli_connect('NULLTest', $user, $pass);
Return false
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-32
tuxedobob
4 months ago
When using this function rather than the OO syntax, this function will return FALSE on error, rather than an object.
up
-34
d4v3m0nk
4 months ago
Worthwhile noting that the MySQLi library can still open a permanent connection, but a different command isn't used. Simply prepend "p:" to the MySQL hostname or address.

Using classes:
$this->mysqli = new mysqli('p:'. mysql_host, mysql_user, mysql_password, mysql_database);

Using command:
$link = mysqli_connect('p:mysql_host', 'mysql_user', 'mysql_password', 'mysql_database');
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